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Algorithms IV · software · environmental consulting

                                 

Applications 2: water contamination · environmental audit and risk · environmental compliance · environmental experts - water · environmental magnagement software · pollution maps · environmental planning · wastewater  · environmental chemistry · outfall and wastewater treatment · outfall and reverse osmosis · marine pollution · environmental consulting 

 

2.1 Water is stratified

 

2.1.1 Multiport diffuser.- We have three different cases: 

Case I: 

θ >=65º   F<=0.1 ó

θ <65º   F<=0.36

θ=angle between Ua vector and diffuser.

F=Fraude number F=Ua3 (g’q)-1

q=Unitary flor rate in the diffuser q=QLt-1 (m2/s)

Q=Discharge flow rate (m3/s)

Lt=Diffuser length (m)

S=initial dilution

In such a case, we have the next relationships

 

S=0.27 Ua H q-1 F-1/3

e=0.29H

B=SQ/eUa

 

Case II: 

 

25o=<θ <65º  F>0,36 (*)

 

In such a case, we have the next relationships

 

S=0.38 Ua H q-1

B=max[Ltsin θ; 0.93Lt F-1/3]

e=SQ/BUa

 

Case III: 

 

θ <25º  0,36<F=<20

 

In such a case, we have the next relationships

 

S=0.294 Ua H q-1 F-1/4

B=max[Ltsin θ; 0.93Lt F-1/3]

e=SQ/BUa

 

Case IV: 

 

θ <25º  F>20

 

In such a case, we have the next relationships

 

S=0.139 Ua H q-1

B=max[Ltsin θ; 0.93Lt F-1/3]

e=SQ/BUa

 

Case V: 

 

θ >65º  F>0,1

 

In such a case, we have the next relationships

 

S=0.58 Ua H q-1

B=max[Ltsin θ; 0,93Lt F-1/3]

e=SQ/BUa

 

From Case II to Case V, and if e>H, we take e=H and S= UaBH/Q.

 

2.1.2 Separated ports.- We will solve this case by means of a iterative mathematical method

 

B=max[Ltsin θ; 0,93Lt F-1/3]

S=0.089 g’1/3 (H-e)5/3 Qb-2/3   (***)

e=SQ/BUa

 

Qb= flow rate at each single port(m3/s).

 

The number of iterations can modify by means of the parameter N_it of the function Calculation parameters of the program.

Increasing N_it value, we increase the numeric convergence but we will need more time of calculation. We should look for an optimized value of N_it.

 

Single port.- In such a case, we have the next relationships

 

 

e=0.15H

S=0.089 g’1/3 (H-e)5/3 Q-2/3

B=SQ/eUa (*)

 

However, at high velocity values and if B<=0.3H, the approximation is not correct .

 

 

 

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